{"id":9522,"date":"2017-10-11T09:49:24","date_gmt":"2017-10-11T14:49:24","guid":{"rendered":"https:\/\/gregladen.com\/blog\/?p=9522"},"modified":"2017-12-05T21:45:18","modified_gmt":"2017-12-06T03:45:18","slug":"mythbusters-on-head-on-collisions","status":"publish","type":"post","link":"https:\/\/gregladen.com\/blog\/2017\/10\/11\/mythbusters-on-head-on-collisions\/","title":{"rendered":"Mythbusters on Head-on Collisions"},"content":{"rendered":"<p>I&#8217;m sure you all have cable and\/or satellite setups and thus see the <a target=\"_blank\" href=\"https:\/\/www.amazon.com\/gp\/product\/B000NO23W6\/ref=as_li_tl?ie=UTF8&#038;camp=1789&#038;creative=9325&#038;creativeASIN=B000NO23W6&#038;linkCode=as2&#038;tag=grlasbl0a-20&#038;linkId=94a2ef77bdb297d731347958e19a9384\">Mythbusters<\/a><img loading=\"lazy\" decoding=\"async\" src=\"\/\/ir-na.amazon-adsystem.com\/e\/ir?t=grlasbl0a-20&#038;l=am2&#038;o=1&#038;a=B000NO23W6\" width=\"1\" height=\"1\" border=\"0\" alt=\"\" style=\"border:none !important; margin:0px !important;\" \/>, which is clearly one of the best things on TV, as they produce them. But I am always a couple of years behind because I watch them on Netflix.  Two more seasons were released on Netflix very recently, so I&#8217;ve been watching them, and I thought one of the Myths addressed was worth bringing up.  <\/p>\n<p>Here&#8217;s the Myth: <!--more--><\/p>\n<p>If a car is going 50 miles an hour and hits an immovable concrete wall, it suffers a certain amount of damage.  If, however, the car hits head on another similar car moving in the opposite direction, then that is like hitting the wall at 100 miles per hour.  This belief is widespread, and it makes sense at first.  Yet, it is wrong.  Having said that, it is actually correct, and when the Mythbusters busted the Myth they may have not noticed that they just busted a perfectly good Myth, and they actually confirmed it while they busted it.  In a way.  <\/p>\n<p>The myth was tested first by using a scale model.  The scale model involved pistons cleverly rigged up with cylinders of mush-able clay. Here was the experimental protocol and results:<\/p>\n<p>1) A pendulum of a fixed weight rigged with mush-able clay is dropped from height A against an immovable object.  The clay gets mushed to P% of it&#8217;s original thickness.<\/p>\n<p>2) The same pendulum rigged the same way is dropped from height B where (B=2A).  The clay gets mushed to 2P% of its original thickness.  This simulates the effects of a 50 mile per hour and a 100 mile per hour collision with a fixed concrete wall, respectively.  <\/p>\n<p>3) The same pendulum is matched up to an identical opposing pendulum.  They are dropped simultaneously from height A. The clay cylinders are found to mush down to P%, not 3P%.  Myth busted in scale model.<\/p>\n<p>Then, of course, they do it with cars.<\/p>\n<p>1) A car is driven at 50 mph against a solid wall. It gets mushed.<\/p>\n<p>2) A second car is driven at 100 mph against the wall.  It gets much more mushed.  <\/p>\n<p>Here are the two cars, the red one was driven at 50 mph, the yellow one at 100 mph:<\/p>\n<p><a href=\"https:\/\/i0.wp.com\/gregladen.com\/blog\/wp-content\/uploads\/2017\/10\/mythbusters_cars.jpg\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"9523\" data-permalink=\"https:\/\/gregladen.com\/blog\/2017\/10\/11\/mythbusters-on-head-on-collisions\/mythbusters_cars\/\" data-orig-file=\"https:\/\/i0.wp.com\/gregladen.com\/blog\/wp-content\/uploads\/2017\/10\/mythbusters_cars.jpg?fit=500%2C251&amp;ssl=1\" data-orig-size=\"500,251\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"mythbusters_cars\" data-image-description=\"&lt;p&gt;Screenshot of an episode of Mythbusters.&lt;\/p&gt;\n\" data-image-caption=\"\" data-medium-file=\"https:\/\/i0.wp.com\/gregladen.com\/blog\/wp-content\/uploads\/2017\/10\/mythbusters_cars.jpg?fit=300%2C151&amp;ssl=1\" data-large-file=\"https:\/\/i0.wp.com\/gregladen.com\/blog\/wp-content\/uploads\/2017\/10\/mythbusters_cars.jpg?fit=500%2C251&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/gregladen.com\/blog\/wp-content\/uploads\/2017\/10\/mythbusters_cars.jpg?resize=500%2C251\" alt=\"\" width=\"500\" height=\"251\" class=\"aligncenter size-full wp-image-9523\" srcset=\"https:\/\/i0.wp.com\/gregladen.com\/blog\/wp-content\/uploads\/2017\/10\/mythbusters_cars.jpg?w=500&amp;ssl=1 500w, https:\/\/i0.wp.com\/gregladen.com\/blog\/wp-content\/uploads\/2017\/10\/mythbusters_cars.jpg?resize=300%2C151&amp;ssl=1 300w\" sizes=\"(max-width: 500px) 100vw, 500px\" data-recalc-dims=\"1\" \/><\/a><\/p>\n<p>3) Two cars are then driven at each other at 50 mph, head-on.  They are both mushed the same as the red car shown above.  Neither car seems to experience a &#8220;100 mph&#8221; collision.<\/p>\n<p>So, the myth is busted in full scale with the actual objects that the myth is about (cars).<\/p>\n<p>But hold on a second, not so fast.  The following two things are also true:<\/p>\n<p>1) With the clay, when two pistons were used, there was sufficient energy to mush two lumps of clay down to the A-height amount, not just one.  <\/p>\n<p>2) With the cars, two cars each suffered the effects of a 50 mph collision.  <\/p>\n<p>Once you either run this all through in your head, or watch the episode, if you previously thought that a pair of cars hitting each other head on at 50 mph would cause one of them to experience a 100 mph collision, then you will absolutely change your mind.  But, if you now think that two cars running into each other at 50 mph each is the same as one car running into a concrete wall at 50 mph, then you&#8217;ve got that wrong. Because, when in the end, you&#8217;ve got two recked cars not one, and the energy used to wreck each of those cars as per a 50 mph collision is twice the energy it would have taken to wreck one of them.<\/p>\n<p>So it is like a 100 mph collision, shared evenly by two cars (so each gets 50 mph worth!)<\/p>\n<p>Here&#8217;s the video:<\/p>\n<p><iframe loading=\"lazy\" width=\"560\" height=\"315\" src=\"https:\/\/www.youtube.com\/embed\/r8E5dUnLmh4\" frameborder=\"0\" allowfullscreen><\/iframe><\/p>\n<p>_______________________<br \/>\nThe show in question is Netflix Season 8 Episode 2, &#8220;Mythssion Control&#8221; subtitle Hyneman vs. Newton.  The numbering, arrangement, and possibly editing of Mythbusters shows on Netflix seems to be different from that aired on TV.  <\/p>\n<p>__________________________<\/p>\n<p>The comments on the original post are interesting and important, generally, so here they are: <\/p>\n<p>makeinu<\/p>\n<p>October 1, 2012\tEdit<br \/>\nWhich is why Mythbusters, great enjoyable TV that it is (and how often can you say that with a straight face) is actually pretty terrible science.<\/p>\n<p>#2<br \/>\nMatty<\/p>\n<p>October 2, 2012\tEdit<br \/>\nHi Greg,<\/p>\n<p>This was my same comment on the show when it first aired. They busted one myth and created a new one. Doing my graduate work in particle physics, I ran into this problem all of the time.<\/p>\n<p>I have been watching to see if they bring this up again, since the conclusions they made were confusing.<\/p>\n<p>#3<br \/>\nTom Pelletier<\/p>\n<p>Long Island<br \/>\nOctober 2, 2012\tEdit<br \/>\nAlthough I love the show, my complaint from a scientific standpoint is that they are often testing things that have at least the possibility of a random component, but they base their \u201cmyth busted\u201d or \u201cmyth confirmed\u201d conclusions on a single trial. I realize the economics of blowing something up 15 times are prohibitive, but in those cases, they should say something.<\/p>\n<p>#4<br \/>\ndaedalus2u<\/p>\n<p>http:\/\/daedalus2u.blogspot.com\/<br \/>\nOctober 2, 2012\tEdit<br \/>\nExcept energy goes as velocity squared. The energy at 100 mph is 4 times that at 50 mph.<\/p>\n<p>If you look at the deformation of the two cars, the 100 mph care has (to my eye) ~4x the deformation of the 50 mph car, which is what you would expect. Energy equals force times displacement the force needed to deform steel or clay in the plastic region is approximately independent of deformation, so it takes a 4 times longer deformation to stop a mass with 4 times more energy.<\/p>\n<p>#5<br \/>\nGreg Laden<\/p>\n<p>October 2, 2012\tEdit<br \/>\ndaedalus 2U: The measurement was the lenght of the car after the crash, and the second car was shortened, it happens, twice as much as the first car. But, squishing in the front of the car is not at all the same as squishing in the next few feet. Also, the second first car got squished. The second car (in the 100 mph hit against the wall) also got flipped. So, right, overall the measurements needed to evaluate all this were not adequate. You really want to crash object that have more uniformity. Big giant force meters.<\/p>\n<p>They did also measure g forces, which I do not report here. But, these are g-forces in the trunk of a crumpling car that may or may not also be flipping and spinning.<\/p>\n<p>#6<br \/>\nEric Lund<\/p>\n<p>October 2, 2012\tEdit<br \/>\nThe myth probably originates from people misidentifying the relevant frame of reference. A solid wall isn\u2019t going anywhere, so the appropriate frame of reference is that where the wall is at rest. But if you are talking about two cars of similar mass, then the relevant frame is not that of the other car, but the frame at which the two cars are approaching at equal speeds from opposite directions (the \u201ccenter of mass\u201d frame). In this example, each car goes from 50 mph abruptly to zero, so each car suffers the effects of a 50 mph collision. The damage is still greater than the scenario where one car at 50 mph hits a stationary car. And if one of the vehicles involved in the head-on collision were a loaded semitrailer, the effect on the car probably would be close to that of a 100 mph collision with a wall.<\/p>\n<p>#7<br \/>\nDave X<\/p>\n<p>October 2, 2012\tEdit<br \/>\nLast sentence:<\/p>\n<p>It is like two 50 mile an hour collisions, shared evenly by two cars.<\/p>\n<p>What one car experiences in the two car collision is exactly the same as what one car experiences in the head-on with the immovable object.<\/p>\n<p>In the clay experiment, you might think of two parallel pendulums side by side, each hitting the immovable object and getting smushed P%.<\/p>\n<p>This might also help in thinking of the difference in cars and pendulums of different sizes. If you had a VW beetle vs a Mack truck collision, it might analogize to clay pendulum vs a 10 times clay pendulum. Head-to head, differently-massed clay pendulums won\u2019t come to a dead stop, like same-massed pendulums, or like clay pendulums against an immovable object.<\/p>\n<p>Also, 2X the speed means 4X the energy, so you\u2019d need to raise the pistons to 4X the height to get to the same energy as double the speed. Doubling the height would get you to 1.414142 times the speed, or only 70.7107 mph.<\/p>\n<p>And the clay\/car-mush-length-percentage-reduction measurement seems odd as well. For example, if you had some lightweight super-long tailfins or spoilers adding to the length, the percentage would go down with the larger divisor while the damage to the front was unchanged.<\/p>\n<p>#8<br \/>\nGreg Laden<\/p>\n<p>October 2, 2012\tEdit<br \/>\nRight. \u2026 people should not make the mistake of thinking that if they run their Ford Pinto at 50 mph into the front of a fully loaded semi head on going at 50 mph that the two vehicles will share that energy evenly. Right? The proper test for Mythbusters would have been to have a car going 50 mph in one direction, and a large steel-clad concrete wall going 50 mph in the other direction\u2026<\/p>\n<p>#9<br \/>\nGreg Laden<\/p>\n<p>October 2, 2012\tEdit<br \/>\nI think it might be necessary for the Mythbusters to get some more cars and trucks and stuff and have another go at this. I also object to not having the gas tanks full at the time of the collisions.<\/p>\n<p>#10<br \/>\nsailor<\/p>\n<p>October 2, 2012\tEdit<br \/>\nThere some level at which I think you are all nuts. Two cars hitting each other at 50 miles an hour is like one car hitting a stationary car at 100 miles an hour. Using a brick wall as a comparison is is like oranges and apples, cars give, brick wall do not. If you can show me that a car hitting a stationary car at 50 miles an hour is the same as two cars hitting head on when both are going 50 miles an hour, I will have to do some serious rethinking. Until then if you are going to crash I suggest you choose another car to hit rather than a brick wall.<\/p>\n<p>#11<br \/>\nGreg Laden<\/p>\n<p>October 2, 2012\tEdit<br \/>\nI would like to see that experiment done: A car going 50mph into an identical car head on instead of into a stationary wall. That, and the \u201cstationary\u201d wall moving at 50 mph. Until these experiments are done, we will not really have a handle on this.<\/p>\n<p>That, and instead of cars we should be using spherical cows.<\/p>\n<p>#12<br \/>\nPhil<\/p>\n<p>October 2, 2012\tEdit<br \/>\nCan someone just compare formulae for me please?<\/p>\n<p>#13<br \/>\nGreg Laden<\/p>\n<p>October 2, 2012\tEdit<br \/>\nGo back 8 comments for the formulae.<\/p>\n<p>#14<br \/>\nlepton<\/p>\n<p>Holland<br \/>\nOctober 2, 2012\tEdit<br \/>\nEk = 0.5 x m x v^2.<\/p>\n<p>So 100 mph results in 0.5 x 2^2 = 2 times the energy, not 4 times.<\/p>\n<p>#15<br \/>\nCherryBombSim<\/p>\n<p>October 2, 2012\tEdit<br \/>\nYou want formulae? Rhett Allain did this one a couple of years ago.<br \/>\nhttp:\/\/scienceblogs.com\/dotphysics\/2010\/05\/06\/mythbusters-and-double-the-spe\/<\/p>\n<p>#16<br \/>\nGreg Laden<\/p>\n<p>October 2, 2012\tEdit<br \/>\nHe addresses a different aspect of this issue in that post. It is interesting, though.<\/p>\n<p>#17<br \/>\nPhil<\/p>\n<p>October 2, 2012\tEdit<br \/>\nOk thanks velocity squared. That makes sense.<\/p>\n<p>#18<br \/>\nGreg Laden<\/p>\n<p>October 2, 2012\tEdit<br \/>\nOh, wait\u2026 we also want to see vehicle A going at 50 mph hitting vehicle B standing still (but head on) and vehicle A going 100 mph and hitting Vehicle B (standing still head on) where vehicles A and B are identical other than the paint job.<\/p>\n<p>#19<br \/>\nGreg Nelson<\/p>\n<p>USA<br \/>\nOctober 2, 2012\tEdit<br \/>\nThankfully I only drive one car, so practically only care what happens to one car. It\u2019s good to know if I\u2019m driving 50 and another car hits me I only receive the damage that I myself would inflict upon myself for driving the same speed and running into an immobile object. Of course a bigger worry for me is the drunk teenager in Bigfoot\u2019s younger brother outweighing me 3 to 1 and traveling at 75 miles an hour. I guess that\u2019 will be addressed in a future program.<\/p>\n<p>#20<br \/>\nEric Lund<\/p>\n<p>October 3, 2012\tEdit<br \/>\nGreg @1712: In the case of the cars, we know what\u2019s going to happen. The fundamental principle of relativity (and this concept predates Einstein; what he was trying to do was to preserve this concept for bodies moving at a noticeable fraction of the speed of light) is that the laws of physics are identical in two frames which differ only in that one is moving at a constant velocity with respect to the other. The actual speed of the two identical cars is irrelevant; only their relative speed matters, and the damage will be as if each car were traveling at half that relative speed. (I\u2019m neglecting what happens after the collision; there will probably be knock-on effects if the center of mass frame has a significant speed.)<\/p>\n<p>Having a moving wall is truly a different experiment from having a stationary wall. The difference is that the stationary wall is anchored to the Earth, but a moving wall can recoil. Relative mass of car and wall becomes important.<\/p>\n<p>#21<br \/>\nPaulG<\/p>\n<p>October 3, 2012\tEdit<br \/>\nIn both cases, a car goes from 50mph to 0 via pressure on the hood, over a few seconds. You\u2019re simply examining two ways of doing the same thing. Somebody mentioned dring a car at 50 mph into a stationary car. That won\u2019t have the same result, it\u2019s going to end up with one car going 25 mph forwards, the other 25 mph backwards. Another case would be a car going 50mph head-on into a truck going 50mph. Result, since the truck weighs about 5x the car, probably a truck going 30-40 mp forward with the car going 50-100 mph backwards, with damage consistent to a 100-150 mph collision. Depends.<\/p>\n<p>#22<br \/>\ndaedalus2u<\/p>\n<p>http:\/\/daedalus2u.blogspot.com\/<br \/>\nOctober 3, 2012\tEdit<br \/>\nEnergy = mgh, dropping something from twice the height does give it twice the energy, not twice the velocity.<\/p>\n<p>As I look at the red and yellow cars, the yellow car is smooshed to about half the total length of the red car, that is after smooshing the red car is 2x the yellow car. I don\u2019t have a before crash image, but the red car doesn\u2019t seem to have that much of its length smooshed. Call it 1\/10 for a 0.9 length after crash. If the yellow car is 0.45 after crash, then the crash compressed 1\/10 of the red car and 0.55 of the yellow car.<\/p>\n<p>This is a front-wheel drive car, so most of the mass is in the front, in the engine and drive train. The stopping of those masses is not mediated through the smooshing of sheet metal (which results in a force ~ independent of deformation and deformation rate), so I see nothing inconsistent with the amount of deformation of the two cars.<\/p>\n<p>#23<br \/>\nMadScientist<\/p>\n<p>October 3, 2012\tEdit<br \/>\nI fail to see how their pendulum experiment is meant to simulate a crash; it\u2019s a bit like the creationist model of the spontaneous generation of animals vs. the scientific model of evolution. In short, the model only makes sense if you know nothing of crashes.<\/p>\n<p>#24<br \/>\nWatching<\/p>\n<p>October 4, 2012\tEdit<br \/>\n? In the case of 2 equal vehicles moving opposite at equal speeds.<br \/>\n\u201cSo it is like a 100 mph collision, shared evenly by two cars\u201d<\/p>\n<p>So what\u2019s the issue? With two identical vehicles, they hit a virtual wall located on the spot where they hit. Each stops dead at that spot, etc.<\/p>\n<p>What else could one reasonably expect?<\/p>\n<p>#25<br \/>\nGreg Laden<\/p>\n<p>October 4, 2012\tEdit<br \/>\ndaedalus2u: As I recall, the lost length of Car 1 is half the lost length of Car 2. But, as you say, the physical layout of mass in the car makes this very difficult to compare.<\/p>\n<p>(That\u2019s why the clay is a good check)<\/p>\n<p>Eric: I like the relativity (not special or general, just relativity) framework for describing this.<\/p>\n<p>MadScientist: I thought it was a good model!<\/p>\n<p>Watching: I think the myth starts with the idea that if you are driving your car along at 50 mph and hit a bridge abutment, that\u2019s bad, but if you hit another car head on, it is wroth. The busting of the myth is to recognize what you said, but I\u2019m adding two elements:<\/p>\n<p>1) It is actually twice as bad in the big picture to hit a similar car travelling at a similar speed because that car gets wrecked as well (this is trivial but I\u2019m not at all convinced it is understood by all onlookers) and<\/p>\n<p>2) If the other car is a semi that weights 30 times the size of your car, that will not be the same as going 50 mph into a bridge abutment. It will, in fact, be worse (for you)<\/p>\n<p>#26<br \/>\nBryan<\/p>\n<p>Oxford<br \/>\nOctober 23, 2013\tEdit<br \/>\nThe myth is based on work done (W=F*D). The work to stop a car of a given weight going a given speed is the same weather that car hits a wall or hits another car going the same speed. Therefore, the damage to the test car will be the same either way. However, the total work done on the system is NOT the same. The difference is that if both cars are moving towards each other, then the work is done twice (Total work = F*D + F*D) but is also spread across two objects, and therefore the SAME amount of work is done to an individual car.<\/p>\n<p>#27<br \/>\ndavid<\/p>\n<p>Europe, EU<br \/>\nOctober 12, 2014\tEdit<br \/>\nThose tested cars have deformation (crumple) zones, the front end is easily crushed, is is engineered so to dissipate the energy by deformation. On the other hand the cabin is reinforced, dissipates energy on a higher scale by deformation, so deforms in length to a lesser degree.<br \/>\nNot to mention, that the \u201creal\u201d moving mass is dropping up to zero when the vehicle is in stand still (in the middle of the collision only the rear section of the car is moving, those having kinetic energy to be dissipated)..<\/p>\n<p>#28<br \/>\nRob Booth<\/p>\n<p>UK<br \/>\nNovember 15, 2014\tEdit<br \/>\nIts true that 2 identical cars in a head on collision at 50mph each suffer equivalent damage to hitting a wall at 50mph. This might lull you into a false sense of security about head on collisions. How about a truck and a car in the same scenario ? I think in this case the car would suffer damage closer to a 100mph impact and the truck a lot less. Due to the different masses the car is likely to end up going backwards after the smash so the change in velocity will be closer to 100mph (+50mph to -50mph). So I think it depends on what you hit and some head on collisions for the smaller vehicle can be very dangerous !<\/p>\n<p>#29<br \/>\nOrionA<\/p>\n<p>USA<br \/>\nApril 3, 2015\tEdit<br \/>\nCars being equal, each car absorbs it\u2019s own energy. Duh. Neither physics models or math are needed to understand this basic idea.<\/p>\n<p>I\u2019ll never grasp why some misguided people think that two same cars hitting each other head on, each going 50, is just like two same cars hitting each other head on each going 100. Um\u2026no.<\/p>\n<p>#30<br \/>\nLoriE<\/p>\n<p>Alberta, Canada<br \/>\nAugust 6, 2015\tEdit<br \/>\nAll I know is that as a passenger in a car going 60 mph being hit head on by another vehicle going 60 mph in the opposite direction, it hurts! I am confused after all your comments. Is this scenario equivalent to driving 120mph into a wall (give or take based on the wall having no give)?<\/p>\n<p>#31<br \/>\ndavid<\/p>\n<p>Europe, EU<br \/>\nAugust 6, 2015\tEdit<br \/>\nFor LoriE: no, it is not the same. As Rob Booth said in comment #28,<br \/>\n\u201cIts true that 2 identical cars in a head on collision at 50mph each suffer equivalent damage to hitting a wall at 50mph.\u201d<br \/>\nand OrionE on #29 \u201cCars being equal, each car absorbs it\u2019s own energy.\u201d<\/p>\n<p>The idea is that the concrete (or better granite) wall does not deformate, and has a much bigger mass than the vehicle that will collide with the wall. So the vehicle will nee to dissipate all the kinetic energy that has at that moment.<\/p>\n<p>When two IDENTICAL car will collide head on, each having the same speed OR NOT, does not matter, that one is stand still, and the other coming with 120 mph, or both having60 mph, the total energy that need to be dissipated is that what counts, and as being identical, both contribute to the kinetic energy absorbtion, they absorb 50:50 of that energy.<br \/>\nBut the concrete wall does not absorb any energy (only a fraction, has almost zero deformation and a much bigger mass).<\/p>\n<p>#32<br \/>\ndavid<\/p>\n<p>August 6, 2015\tEdit<br \/>\nWhen the car is hitting a concrete wall is like the fat bug hittig the windscreen at 120 mph, the windscreen has a much higher mass than that bug, and does not deformate, so the bug will make itself a greasy patch, so you need to use the windscreen washer.<\/p>\n<p>#33<br \/>\ndavid<\/p>\n<p>August 6, 2015\tEdit<br \/>\nSo in conclusion, just a question of life or death:<\/p>\n<p>You are driving your Bentley Continental GT with all your family or loved ones at 80 mph on a one way road that will enter into a concrete reinforced tunnel, only one car can pass.<br \/>\nThen suddenly you see another identical car with the same \u201cmass\u201d of people coming from the tunnel at\u2026let\u2019s say 70 mph, so a little less than your speed. I have not choosed 120\/110 mph, so you have some chances for survival, so keep your speed down.<br \/>\nWhat will you do to maximalize the survival of your genes, not caring that if you choose B then you can hurt other people (although they are coming on a one way road at the wrong direction, so theoretically they would \u201cdeserve\u201d it).<br \/>\nAlso you have no time to press the brake pedals (or there is a brake failure) you can only choose the direction of travel:<\/p>\n<p>Answer A: You corner into the concrete wall next to the tunnel entrance, colliding at 80 mph<\/p>\n<p>Answer B: You continue your way of travel, colliding with the identical car at 150 mph.<\/p>\n<p>???<\/p>\n<p>#34<br \/>\nJamie Hanrahan<\/p>\n<p>California<br \/>\nAugust 31, 2015\tEdit<br \/>\nAny explanation that tries to equate the two cars\u2019 hitting each other at 50 mph with one hitting a wall at 100 mph is wrong. kinetic energy = one half of emm vee squared. One car at 100 mph has four times the ke of a car at 50 mph. Two cars each at 50 mph only have, collectively, half of the kinetic energy of the single car moving at 100 mph. The car in the second case therefore has to dissipate (by being deformed) twice as much energy as each car in the first case. And that was completely confirmed by the Mythbusters\u2019 results. Any other interpretation is clever, but misleading, wordsmithing.<\/p>\n<p>#35Jon<\/p>\n<p>US<br \/>\nOctober 29, 2015\tEdit<br \/>\nWhy so much analyzing? Both vehicles met @zero. Mathematically 1-1 is zero. Both vehicles are the same. If they would of have put a different vehicle or a heavier vehicle the smaller vehicle would had sustain more damage than the heavier vehicle. 2-1 equals to 1. This has been explained before just in numbers there is no need to proof theory wrong.<\/p>\n<p>#36<br \/>\nDan<\/p>\n<p>Florida<br \/>\nDecember 30, 2015\tEdit<br \/>\nJamie hanrahan, you are almost correct. However the whole exp riment is tainted. Evryone on these posts are discussing kinetic energy. However the outcome is being measured byndamage to a car. Damage is not done by energy but by decceleration. Running a 100mph car into a perfectly rigid and infinite mass wall will do more damage than running a 100 mph into a stationary car due to the plastic deformation. Therefore you cannot measure the impact based on appearance since the car vs wall and car vs car are not identical scenarios. Unlike what PaulG said this is not a perfeclty elastic collission so a 100mph car and stationary car wont move in opposite directions. They will create a heap of metal. Anyways, there will be a greater impact of two cars hitting at 50mph head in than a sungle csr hitting a stationary car at 50 mph due to the split of energy between the two masses.<\/p>\n<p>#37<br \/>\nSanthosh<\/p>\n<p>kasaragod<br \/>\nMarch 25, 2016\tEdit<br \/>\ngood post<\/p>\n<p>#38<br \/>\nThe IIHS confirms The Ford F150 as the safest full size pickup &#8211; Page 2 &#8211; Ford Inside News Community<br \/>\nApril 14, 2016\tEdit<br \/>\n[\u2026] because even-though the &#8220;impact&#8221; is at 100, but they both take a portion of the impact http:\/\/scienceblogs.com\/gregladen\/20\u2026on-collisions\/ Now if they were the same size 50\/50 split would be expected, I am not at all sure how much that [\u2026]<\/p>\n<p>#39<br \/>\nMCRodgers2<\/p>\n<p>San Diego, CA<br \/>\nMay 18, 2016\tEdit<br \/>\n\u201c3) The same pendulum is matched up to an identical opposing pendulum. They are dropped simultaneously from height A. The clay cylinders are found to mush down to P%, not 3P%.\u201d<\/p>\n<p>Did you mean to to type here, \u201cP%, not 2P%\u201d instead of 3P% ???<\/p>\n<p>#40<br \/>\nDoug<\/p>\n<p>Austin, TX<br \/>\nMay 20, 2016\tEdit<br \/>\ndavid \u2014<\/p>\n<p>To answer your question, since your car is going a bit slower than the other, and since we don\u2019t care about hurting anybody else \u2014 all we care about is ourselves \u2014 and I assume that the tunnel wall is 100% rigid and immovable \u2026 it would be slightly better to hit them head on than to hit the tunnel wall.<\/p>\n<p>And if the two speeds were equal, it wouldn\u2019t matter which one you did \u2014 both would result in approximately equal damage to your car and yourself.<\/p>\n<p>#41<br \/>\n2016 American muscle cars Crash Test &#8211; Video<br \/>\nMay 24, 2016\tEdit<br \/>\n[\u2026] did a good job on that issue of mass and speed in collisions. Turns out ol&#8217; Newton was right:http:\/\/scienceblogs.com\/gregladen\/20\u2026on-collisions\/ At the same time \u2013 they may have gotten it wrong, while getting it right..right?!? The mass of two [\u2026]<\/p>\n<p>#42<br \/>\nQuestion<\/p>\n<p>September 11, 2016\tEdit<br \/>\nI get it for hitting a wall that is that force is mainly distributed to crush the car while wall provided it doesnt move and is really solid doesnt absorb much.<br \/>\nBut\u2026<br \/>\nIf we would replace the wall with not moving car then that comparision (2*stat = 1*head on) will be true right?<\/p>\n<p>#43<br \/>\nBrainstorms<\/p>\n<p>September 11, 2016\tEdit<br \/>\nQuestion, don\u2019t miss the assumptions in your #42 that the wall is \u201csolid and immutable\u201d, and therefore absorbs some of the energy of impact without any substantial damage\u2026<\/p>\n<p>Whereas your \u201cnot moving car\u201d differs considerably: It is SIGNIFICANTLY lower in mass than the wall (which is presumed to be so massive that it can be treated as having essentially infinite mass for the purposes of calculating the collision effects), and it is \u201cplastic\u201d, in that the energy of collision will very significantly \u2013and easily\u2013 deform the second car.<\/p>\n<p>The deformation will absorb some of the energy of collision, while having a mass comparable to the moving car will result in it acquiring a velocity post-impact.<\/p>\n<p>In short, you have a very different physics problem if you replace the wall with a stationary car\u2026<\/p>\n<p>#44<br \/>\nAkash Phalak<\/p>\n<p>India<br \/>\nOctober 6, 2016\tEdit<br \/>\nhi guys, In my project of accident detection i m using accelerometer to detect impact and i m placing it at footweel(driver foot place) in car so which g value sensor do i need for appropriate detection.<br \/>\ni m confuse about 40 to 50 or 100g sensor. i think the main concern here is the place where we can place our sensor(accelerometer).<\/p>\n<p>#45<br \/>\nMartin Pedersen<\/p>\n<p>Denmark<br \/>\nNovember 11, 2016\tEdit<br \/>\nHello.<br \/>\nI was thinking about the test with the 2 cars crashing with 50 mp\/h. But what if car 1 was at 0 mp\/h and car 2 at 100 mp\/h.<br \/>\nSame result?<\/p>\n<p>#46<br \/>\nDavid<\/p>\n<p>Georgia<br \/>\nNovember 20, 2016\tEdit<br \/>\nThis is all fun theory but bottomline:<\/p>\n<p>Head-on collisions are VERY DANGEROUS!<\/p>\n<p>Better to nudge or side swipe car going in same direction or hit a small stationary object.<\/p>\n<p>P.s. who would drive head on into a solid wall?<\/p>\n<p>#47<br \/>\njay<\/p>\n<p>here and there, but KAzakhstan right now<br \/>\nFebruary 24, 2017\tEdit<br \/>\nthey didn\u2019t actually test the myth \u2013 a third test of one car going 100 mph hitting a stationary one was the missing point. Assuming the two masses are the same and ignoring road friction and other minor annoyances, the math is pretty straightforward . if a moving mass hits a stationary mass and neither deforms (think of a newtons cradle with only two balls) the moving mass stops and the second accelerates away and is soon moving at the same speed and direction that the first had. If the masses connect and lock together but do not deform, the new blob of twice the mass will move in the same direction as the initially moving mass, but (in this case) at around 70.7 mph. If both masses deform (momentum, kinetic energy converting into deformation and heat) both masses travel in the same direction as the initial mass at some speed less than 70.7 mph \u2013 and because they are still moving, (and still have some energy) the deformation to each is likely to look like 50mph for vehicles with moderate deformability IMHO. Look at it one more way, if a moving car hit a stationary car backed up to touch the wall, at 50mph, some energy would deform the moving car, and both ends of the stationary one. At 100 mph, the deformation would be 4X the energy spread out where the two vehicles touch each other and where one touches the wall The myth IS busted no matter what.<br \/>\nTL;DR one car, 50mph, strong wall \u2013 energy converted to smush =X, car stops. Two cars, each 50mph, hit each other \u2013 energy converted to smush =2X, each gets half, both stop. Two cars, one 100mph and the other zero, energy AVAILABLE to convert to smush =4X \u2026 identical smush would be related to the final speed of the still moving combined mass..<br \/>\nsuper TL;DR: one car moving at 50, hits wall and stops, energy is X, car absorbs it. Two cars moving at 50 hit each other, energy is 2X spread over 2 cars, therefore same outcome as hitting the wall \u2013 all STOP. if one moving 2 times speed and other zero, energy is 4X the lower speed, both cars will smush, and the combined mass is STILL moving after the collision (with the possibility for more smushing \u2013 where is that wall exactly?).<br \/>\nMyth busted with math.<\/p>\n<p>#48<br \/>\nKelly<\/p>\n<p>Atx<br \/>\nSeptember 8, 2017\tEdit<br \/>\nHere\u2019s what you knuckleheads aren\u2019t understanding\u2026 it\u2019s actually not about what the cars experience, but what the PEOPLE driving the car experience. They are not only feeling half of the impact, they are feeling 100% of the force of the impact.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>I&#8217;m sure you all have cable and\/or satellite setups and thus see the Mythbusters, which is clearly one of the best things on TV, as they produce them. But I am always a couple of years behind because I watch them on Netflix. Two more seasons were released on Netflix very recently, so I&#8217;ve been &hellip; <a href=\"https:\/\/gregladen.com\/blog\/2017\/10\/11\/mythbusters-on-head-on-collisions\/\" class=\"more-link\">Continue reading <span class=\"screen-reader-text\">Mythbusters on Head-on Collisions<\/span> <span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":9524,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5025,5035],"tags":[1065,1064,5020],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/i0.wp.com\/gregladen.com\/blog\/wp-content\/uploads\/2017\/10\/MythBusterEnd_FEAT.jpg?fit=970%2C545&ssl=1","jetpack_shortlink":"https:\/\/wp.me\/p5fhV1-2tA","jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/posts\/9522"}],"collection":[{"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/comments?post=9522"}],"version-history":[{"count":3,"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/posts\/9522\/revisions"}],"predecessor-version":[{"id":9527,"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/posts\/9522\/revisions\/9527"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/media\/9524"}],"wp:attachment":[{"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/media?parent=9522"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/categories?post=9522"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gregladen.com\/blog\/wp-json\/wp\/v2\/tags?post=9522"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}